Given an array of strings, return another array containing all of its longest strings.

Example

For inputArray = ["aba", "aa", "ad", "vcd", "aba"], the output should be

allLongestStrings(inputArray) = ["aba", "vcd", "aba"].

Input/Output

• • [execution time limit] 4 seconds (py3)

  • [input] array.string inputArray

    A non-empty array.

    Guaranteed constraints:

    1 ≤ inputArray.length ≤ 10,
    1 ≤ inputArray[i].length ≤ 10.

  • [output] array.string

    Array of the longest strings, stored in the same order as in the inputArray.

 

 

我的解答：

1 def allLongestStrings(inputArray):2     li = []3     m = max(inputArray,key=len)4     for i in inputArray:5         if len(i) == len(m):6             li.append(i)7     return li

 

膜拜大佬：

1 def allLongestStrings(inputArray):2     m = max(len(s) for s in inputArray)3     r = [s for s in inputArray if len(s) == m]4     return r

 

虽然代码比大佬写的多，但至少想法一样了....